a 63.5 sample of an unindentified metal absorb 355 J of heat when it's temperature changed by 4.56°C. calculate the specific heat capacity of the metal
1. a 63.5 sample of an unindentified metal absorb 355 J of heat when it's temperature changed by 4.56°C. calculate the specific heat capacity of the metal
Jawaban:
maaf kalo salah......
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2. A piece of metal weighing 4 kg is heated from 25 Degrees Celsius to 55 degrees Celsius. The heat needed is 12,000 Joules. A. Calculate the heat capacity of the metal b. Calculate the specific heat capacity of the metal.
A.
Q = C . delta T
12000 = C . ( 55 - 25 )
C = 400 J/C
B.
C = m . c
400 = 4 . c
c = 100 J/KgC
3. 1. Heat capacity of a metal whose specific heat is 1.500 J/kg °C is 6 kJ/°C. The mass of the metal is …2. Given 200 joule of heat, the temperature of a metall with 100 gram mass increases 20oC. If the heat given is 1000 joule, the incease of its temperature is ...Tolongin ya kak deadlinenya besok :<
Jawaban:
4kg, 100°c
Penjelasan:
Q=mc
6000=1500*m
m=4 kg
Q=mc∆t
200=(0,1)*c*20
c=100 J/Kg°C
1000=(0,1)*c*∆t
1000=10∆t
∆t=100°C
4. A 15.75-g piece of iron absorbs 1086.75 joules of heat energy, and its temperature changes from 25°C to 175°C. Calculate the specific heat capacity of iron.
Penjelasan:
may the solution help you and don't forget to follow me please (^^)
5. 5. Calculate the amount of heat needed to raise the temperature of 1.5 kg water from 300C to 800C. (specific heat of water= 1 kcal/kg0C)
Jawaban:
750.000 kal = 750 kkal
Penjelasan:
Diketahui :
m = 1,5 kg
c = 1 kkal/(kg °C)
ΔT = T2 - T1 = 800°C - 300°C = 500°C
Ditanya : Q = ... kal?
Jawab :
Q = m c ΔT
Q = 1,5 kg (1 kkal/(kg °C)) (500°C)
Q = 750 kkal
Q = 750.000 kal
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6. 5. A block of copper of specific heat of 385 J/kg°C at a temperature of 95°C with 5 kg of mass is dropped into water of 2.5 kg of mass at a temperature of 15°C. If the specific heat of water is 4200 J/kg°C what is the final temperature of copper?
Jawaban :
Penjelasan:
Q lepas = Q terima
m . c . ~T = m . c . ~T
5 × 385 × (95 - Tc) = 2,5 × 4200 × (Tc - 15)
1925 × (95 - Tc) = 10500 × (Tc - 15)
385 × (95 - Tc) = 2100 × (Tc - 15)
55 × (95 - Tc) = 300 × (Tc - 15)
11 × (95 - Tc) = 60 × (Tc - 15)
1045 - 11Tc = 60Tc - 900
1945 = 71.Tc
Tc ≈ 27,4°C
7. How many joules are energy required to melting 100g ice 0"C becomes water 50'C. Specific laten heat of fusion = 336.000 J/Kg Specific heat capacity of water = 4200 J/Kg "C
Jawaban:
energy required 54.600joule or 54,6KJ
Penjelasan:
cara difoto
8. An object with a mass of 200 g has a heat capacity of 104 J/oC. The specific heat of the substance is
Jawaban:
520 J/Kg C
Penjelasan:
diketahui :
m = 200 = 0,2
C = 104 j/kg C
ditanya :
c = ..... ?
dijawab :
c = C/m
= 104/0,2
= 520 j/kg C
9. 3. The2.5 kg metal barreceives850Jouleheat energy.Calculate the specific heat(In J/kg0C)ifthe metal bar is heated from 300C to 1200C.
Untuk menentukan kalor jenisnya kita bisa menggunakan persamaan umum dari kapasitas kalor, sehingga didapatkan kalor jenisnya adalah: 0,378 J/kg°C
Penjelasan dengan langkah-langkahDiketahui: Batang logam yang memiliki berat 2,5 kg (m) menerima energi kalor 850 Joule (Q), batang logam dipanaskan dari 300C hingga 1200°C (ΔT = 1.200 - 300 = 900°C)Ditanya: Hitung kalor jenis (Dalam J/kg°C)?JawabRumus untuk menentukan kapasitas kalor adalah:
C = m x c
Dengan:
m = massa benda (kg)
c = kalor jenis J/kg°C
atau, C = (m x c x ΔT) : ΔT
Dengan:
ΔT = Perubahan suhu (°C)
Maka, rumus untuk menentukan kalor jenis (c) adalah:
c = Q : (m x ΔT)
c = 850 : (2,5 x 900)
c = 850 : 2.250
c = 0,378 J/kg°C
Pelajari lebih lanjutMenentukan kalor jenis: https://brainly.co.id/tugas/6432845
#BelajarBersamaBrainly
10. An object with a mass of 200 g has a heat capacity of 104 J/oC. The specific heat of the substance is.
An object with a mass of 200 g has a heat capacity of 104 J/°C. The specific heat of the substance is 20.8 J/kg°C
Solution:
Known:
m = 200 gram = 0,2 kg
C = 104 J/°C
Asked:
c = ...?
Answer:
c = m × c
= 0,2 × 104
= 20.8 J/kg°C
So, the specific heat of the substance is 20.8 J/kg°C.
11. An object with a mass of 200 g has a heat capacity of 104 J/oC. The specific heat of the substance is
An object with a mass of 200 g has a heat capacity of 104 J/°C. The specific heat of the substance is 20.8J/kg°C
Solution:Known:
m = 200 gram = 0,2 kg
C = 104 J/°C
Asked:
c = ...?
Answer:
c = m × c
= 0,2 × 104
= 20.8J/kg°C
So, the specific heat of the substance is 20.8 J/kg°C.
12. A block of aluminum weighing 140 g is cooled from 98.4°C to 62.2°C with the release of 4560 joules of heat. From this data, calculate the specific heat of aluminiumhelp please
Jawaban:
rumus, cara, dan jawabannya seperti di foto.
semangat belajar
#Pertamax
13. 500 grams of ice at -10^oC will be melted down to become water at 5^oC. If the specific heat of ice is 0.5 cal/gr^oC, the heat of fusion for ice is 80 cal/gr and the specific heat of water is 1 cal/gr^oC. Determine the amount of heat needed * 20 poin
Jawaban:
Penjelasan:
- heat absorbed to reach 0 degree C
[tex]Q_1=mc\Delta T=500 gram\times 0.5 cal/gramK\times (0-(-10))K=2500 cal[/tex]
- heat absorbed to make it water
[tex]Q_2=mL=500gram\times 80 cal/gram=40000 cal[/tex]
- heat absorber to reach 5 degree C of water
[tex]Q_3=mc\Delta T=500 gram times 1 cal/gramK\times (5-0)K=2500 cal[/tex]
total heat absorbed
[tex]Q=Q_1+Q_2+Q_3=2500cal+40000cal+2500cal=45000cal[/tex]
14. berapa specific heat dari cabai merah???? totong ya....
Skala Scoville, adalah ukuran tentang pedasnya cabai. Jumlah Satuan pedas Scoville (SHU) menunjukkan jumlah capsaicin yang ada padanya.
krn begitu banyak jenis cabai merah dan kandungan capsaicin yang berbeda pula, kamu bisa melihat tabel SHU di:
id.m.wikipedia.org/wiki/Skala_Scoville
ok, smoga membantu, salam...
15. Metal (expand)......... If you (heat)........ It.
Metal will expand if you are heating it
16. An object with a mass of 200 g has a heat capacity of 104 J/oC. The specific heat of the substance is
Jawaban:
520 J/Kg C
diketahui :
m = 200 = 0,2
C = 104 J/C
ditanya :
c = ?
dijawab :
c = C/m
c = 104/0,2
c = 520 J/Kg C
17. The metal bar receives 1250 joule heat energy and has a specific heat of 650 j/kg^ 0 c what is the mass (kilogram) if the metal bar is heated from 45 degrees*c to 110 degrees *c ?
Jawaban:
Q = mcΔT
1250 J = m.650 J/kg°C.(110-45) °C
1250 J = m.650 J/kg°C.65 °C
m = 1250 J/(650 J/kg°C.65 °C)
m = 5/169 kg = 0,0296 kg
18. If the specific heat of water is 1000 J/kg°C, how much heat is required to heat 2 kg of water from 230°C to 1000°C?
Jawaban:
Penjelasan:
t= 1000-230= 770 celcius
m= 2kg
1000J/kg°C x 770 x 2 = 1.540.000 joule
19. Factor that depend heat is A.mass, temperature, and weight B.mass, specific latent heat, weight C.mass, specific latent heat, temperature D.mass, specific letent heat, weight
Jawaban:
c
Penjelasan:
seemoogaa meemmmbannntuuu
20. Answer key of reading power by longman
Jawaban:
kunci jawaban "kekuatan membaca" oleh logman
Jawaban:
kunci jawaban kekuatan membaca oleh longmen
Penjelasan:
semoga membantu
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