>>> Permutations- Blank- Room- SoupNote: Anyone dare to watch this video? cannibal videos!
1. >>> Permutations- Blank- Room- SoupNote: Anyone dare to watch this video? cannibal videos!
Blank
= 5 huruf
= 0 unsur ganda
= 5!
= 5 x 4 x 3 x 2 x 1
= 20 x 6 x 1
= 120 susunan kata
Room= 4 huruf
= 1 unsur ganda (o) = 2
= 4!/2!
= 4 x 3 x 2 x 1 / 2 x 1
= 4 x 3
= 12 susunan kata
Soup= 4 huruf
= 0 unsur ganda
= 4!
= 4 x 3 x 2 x 1
= 24 susunan kata
Penjelasan dengan langkah-langkah:
Blank
Total Huruf=5
P=n!
P=5!
P=5×4×3×2×1
P=120 Susunan kata
Room
Total Huruf=4
Unsur Ganda=2
P=n! /k!
P=4! / 2!
P=4×3×2×1 / 2×1
P=24 / 2
P=12 Susunan
Soup
Total Huruf=4
P=n!
P=4!
P=4×3×2×1
P=24 Susunan kata
2. >>> Permutations Permutations Of-zkzkzkzkzkzkkzkzkzkzkkzkzkz
Jawaban:
-zkzkzkzkzkzkkzkzkzkzkkzkzkz
Z:13
K:14
27!/13/14=5,98289530E+25
Penjelasan dengan langkah-langkah:
#AnswerbySititik#
3. Permutations- Recruiter- MagicVision
soal 1 >>
R 1
E 2
C 3
U 4
I 5
T 6
E 7
R 8
Banyak huruf = 8
unsur ganda = 4n!
8×7×6×5×4×3×2×1=
40.320 banyak susunan kata
soal 2>>m 1
a 2
g 3
i 4
c 5
v 6
i 7
s 8
i 9
o 10
n 11
banyak huruf = 11
unsur ganda : =
11×10×9×8×7×6×5×4×3×2×1=
total : 39.961.800
[tex]{\red{\boxed{\colorbox{orange}{\green{{ note:maap \: apabila \: salah }}}}}}[/tex]
Jawaban:
RECRUITERR = 3E = 2C = 1U = 1I = 1T = 1--------- +TOTAL HURUF = 9UNSUR GANDA = 3(R); E(2)P=n!/k!
P=9!/3!×2!
P=9×8×7×6×5×4×3×2×1/3×2×1×2×1
P=362.880/12
P=30.240SUSUNANKATA.
MAGICVISIONM = 1A = 1G = 1I = 3C = 1V = 1S = 1O = 1N = 1-------- +TOTAL HURUF = 11UNSUR GANDA = 3P=n!/k!
P=11!/3!
P=11×10×9×8×7×6×5×4×3×2×1/3×2×1
P=39.916.800/6
P=6.652.800SUSUNANKATA.
DETAILJAWABAN:Mapel : MatematikaKelas : 12Bab : Kaidah PencacahanKode Soal : 2Kode Kategorisasi : 12.2.7Kata Kunci : Permutasi4. Quiz>>> Permutations - éltan - Pein- Anij------->>> Permutations #2- Eim- Woj- Romak #SpamCode#ÉltanPeinAnij2021ßřàíñĺý
Penjelasan dengan langkah-langkah:
eltan
n = 5
5!
120 susunan kata
____________________
pein
n = 4
4!
24 susunan kata
___________________________
anij
n = 4
4!
24 susunan kata
======================================
eim
n = 3
3!
6 susunan kata
_________________
woj
n = 3
3!
6 susunan kata
__________________
romak
n = 5
5!
120 susunan kata
Permutasi 1EltanE - 1
L - 1
T - 1
A - 1
N - 1
------- +
= 5
Unsur kata => 5!
Unsur Ganda => -
P! = 5!/1!
= 120!/1!
= 120!
PeinP - 1
E - 1
I - 1
N - 1
------- +
= 4
Unsur kata => 4!
Unsur Ganda => -
P! = 4!/1!
= 24!/1!
= 24!
AnijA - 1
N - 1
I - 1
J - 1
Unsur kata => 4!
Unsur Ganda => -
P! = 4!/1!
= 24!/1!
= 24!
Permutasi 2EimE - 1
I - 1
M - 1
-------- +
= 3
Unsur kata => 3
Unsur ganda => -
P! = 3!/1!
= 6!/1!
= 6!
WojW - 1
O - 1
J - 1
------- +
= 3
Unsur kata => 3
Unsur ganda => -
P! = 3!/1!
= 6!/1!
= 6!
RomakR - 1
O - 1
M - 1
A - 1
K - 1
------- +
= 5
Unsur kata => 5!
Unsur Ganda => -
P! = 5!/1!
= 120!/1!
= 120!
5. >>> Permutations - Cyka- ‘Blyad
Penjelasan dengan langkah-langkah:
cyka
jumlah kata=4
unsur ganda=-
4x3x2x1=24 susunan kata✓
BIyad
jumlah kata=5
unsur ganda=-
5x4x3x2x1=120 susunan kata✓
semoga bermanfaat untuk kita semua
answer: mosespartogihutagaol
6. Permutations- Question- Too - LongNote: Permutations are lessons, not for all kinds :z
Question
Total Unsur = 8
Total Ganda = -
Banyak Susunan := 8!
=40.320Susunan kata✓
TooTotal Unsur = 3
Total Ganda = 2(o)
Banyak Susunan := 3! / 2!
= 6 / 2
=3Susunan kata✓
LongTotal Unsur = 4
Total Ganda = -
Banyak Susunan := 4!
=24Susunan kata✓
Penjelasan dengan langkah-langkah:
1) question
jumlah huruf = 8
unsur ganda = 0
permutasi
= n!
= 8!
= 8×7×6×5×4×3×2×1
= 40320
2) too
jumlah huruf = 3
unsur ganda = 2
permutasi
= n!/k!
= 3!/2!
= 3×2×1/!2×1
= 3
3) long
jumlah huruf = 4
unsur ganda = 0
permutasi
= n!
= 4×3×2×1
= 24
keterangan:
n = jumlah obyek/unsur/simbol
k = unsur ganda
7. >>> Permutations - Good - Night>>> Permutations 2- God- Save- World
Permutasi
Good = 5!
5! = 5x4x3x2x1
= 120
Night = 5!
5! = 5x4x3x2x1
= 120
Permutasi Ke dua
God = 3!
3! = 3x2x1
= 6
Save = 4!
4! = 4x3x2x1
= 24
World = 5!
5! = 5x4x3x2x1
= 120
Semoga Membantu
8. Permutations of the word "Alhamdulillah"
Penjelasan dengan langkah-langkah:
-Alhamdulillahjumlah huruf:13!
unsur ganda:3!,4!,2!,
13×12×11×10×9×8×7×6×5×4×3×2/3×2×4×3×2×2
=6.227.020.800/288
=21.621. 800 susunan
Permutations_________________________
Alhamdulillah = 21.621.600 susunan
Penjelasan :Alhamdulillah
Jumlah unsur 13!Unsur ganda a(3).l(4).h(2)= n! / k!
= 13! / 3!.4!.2!
= 6.227.020.800 /
= 21.621.600 susunan
#Kookaburra9. Let's Quiz AgainPermutations- Override
Jawaban:
OVERRIDE
OVERRIDE=8.7.6.5.4.3.2.1
=40.320÷2
=20.160
#CMIIW
- override
number of letters : 8
double letter :
2 ( r )
2 ( e )
step by step
8!
_____
2! × 2!
8! = 40,320
2! = 2
• 10,080 word order
sorry if wrong
please correct the answer
see you on the next Quiz :}
10. QuizPermutations - Konstantinopel
- konstantinopel
number of letters: 14
double letter :
- 2 ( o )
- 2 ( t )
- 3 ( n )
step by step
14!
________
2! × 2! × 3!
14! = 87,178,291,200
2! = 2
3! = 6
• 3,632,428,800 word order
sorry if wrong
see you on the next Quiz :)
11. Amoeba membelah diri menjadi 2 setiap 10 menit. Jika mula mula terdapat 20 amoeba. Maka banyak amoeba selama 1 jam adalah ..5 poinA. 640 amoebaB. 1.280 amoebaC. 320 amoebaD. 2.560 amoeba
Jawaban:
Jawabannya = 1.280 amoeba
Penjelasan dengan langkah-langkah:
60 mnt : 10 mnt = 6
20 × 2 = 40 × 2 = 80 × 2 = 160 × 2 = 320 × 2 = 640 × 2 = 1.280
Semoga Membantu
12. >>> Permutations - Hehe- Boi-.-
Jawaban:
≈ PENDAHULUAN KAIDAH PENCACAHAN HEHEBOI≈ MAKAHEHE=H=E=H=E=4.3.2.1
=24÷4
=6
BOI=B=O=I=3.2.1
=6
SEMOGA MEMBANTU
[tex]{}[/tex]
>> Permutαsi• HeheTotal huruf : 4Unsur Ganda : 44!4 x 3 x 2 x1 / 4 x 3 x 2 x 1 24 / 241 Susunan Kata• Boi Total Huruf : 3Unsur Ganda : -3!3 x 2 x 1 6 Susunan Kata[tex] \pink { Answer :ㄨNana }[/tex]
13. berikan penjelasan mengenai framehsift mutations!
Framehsift mutations adalah penambahan atau pengurangan basa nitrogen. Mutasi ini terdiri dari delesi( pengurangan basa nitrogen) dan duplikasi ( penambahan basa nitrogen)
14. Permutations:• uvuvuevuevue • enyetuenwuevue• ugbemugbem• osas-Curious
Explanation:
Permutations are different arrangements or sequences that are formed from part or all of the objects.
➽ The formula for permutations without double elements is P = n!
➽ The formula for permutations with multiple elements is [tex]P = \frac{n!}{k!}[/tex]
➽ The formula for a cyclical permutation is (n – 1)!
**
A combination is a collection of some or all objects regardless of their order.
➽ The formula for the combination is C(n, r) = n!/(r! (n – r)!
**
Factorial, which is sequential multiplication and starts or starts from the number 1 to the number in question, so the factorial of a natural number is the result of multiplying positive integers and less than or also with n.
Example factorial =
[tex]\begin{gathered} \boxed{ \begin{array}{c|c} \underline{\rm Factorial\:Number} & \underline{ \rm Result}\\ \rm1!&\rm 1 \\ \rm 2! & \rm 2\times1=2\\ \rm 3! & \rm 3\times2\times1=6\\ \rm4! & \rm 4\times3\times2\times1=24\\ \rm 5! & \rm 5\times4\times3\times2\times1=120\\ \rm 6! &\rm 6\times5\times4\times3\times2\times1=720\\ \rm 7! &\rm 7\times6\times5\times4\times3\times2\times1=5.040\\ \rm 8! &\rm 8\times7\times6\times5\times4\times3\times2\times1=40.320\\ \end{array}}\end{gathered}[/tex]
*note: if the result of the factorial number in the box is not visible, swipe to the side
Jawab:
• uvuvuevuevue = 27.720 word order
• enyetuenwuevue = 60540480 word order
• ugbemugbem = 362.880 word order
• osas = 12 word order
Penjelasan dengan langkah-langkah:
"uvuvuevuevue"
u = 5
v = 4
e = 3
Number of letters = 12Double element = letter u(5), letter v(4) and letter e(3)[tex]P = \frac{n!}{k!} = \frac{12!}{5! \times 4! \times 3!} = \frac{479.001.600}{17.280}[/tex]
[tex]\boxed{\tt {{\colorbox{pink}{P = 27.720 word order}}}}[/tex]
────────────── ೄྀ࿐ ˊˎ-
"enyetuenwuevue"
e = 5
n = 2
y = 1
t = 1
u = 3
w = 1
v = 1
Number of letters = 14Double element = letter e(5), letter n(2) and letter u(3)[tex]P = \frac{n!}{k!} = \frac{14!}{5! \times 3! \times 2!} = \frac{87.178.291.200}{1.440}[/tex]
[tex]\boxed{\tt {{\colorbox{pink}{P = 60.540.480 word order}}}}[/tex]
────────────── ೄྀ࿐ ˊˎ-
"ugbemugbem"
u = 2
g = 2
b = 2
e = 2
m = 2
Number of letter = 10Double element = all letters have 2 double elements[tex]P = \frac{n!}{k!} = \frac{10!}{2! \times 2! \times 2! \times 2! \times 2!} = \frac{3.628.800}{10}[/tex]
[tex]\boxed{\tt {{\colorbox{pink}{P = 362.880 word order}}}}[/tex]
────────────── ೄྀ࿐ ˊˎ-
"osas"
o = 1
s = 2
a = 1
Number of letter = 4Double element = letter s(2)[tex]P = \frac{n!}{k!} = \frac{4!}{2!} = \frac{4 \times 3 \times 2 \times 1}{2 \times 1} = \frac{24}{2}[/tex]
[tex]\boxed{\tt {{\colorbox{pink}{P = 12 word order}}}}[/tex]
────────────── ೄྀ࿐ ˊˎ-
Learn More:Permutations of words "Ijin", "Off", "Mulai", "Besok" = brainly.co.id/tugas/44865081word order of "Squid Game" = brainly.co.id/tugas/45040607how many word order of -Selesai -Sudah -Kuis -Nyaa = brainly.co.id/tugas/45089792Answer Details:Subjects: Mathematics
Class: 12 High School
Material: Chapter 7-rules of counting
Categorization Code: 12.2.7
Keywords: Permutations of the word
15. Quiz Permutations of:Thyroparathyrodheisazeyia
Explanation:
Permutations are different arrangements or sequences that are formed from part or all of the objects.
➽ The formula for permutations without double elements is P = n!
➽ The formula for permutations with multiple elements is [tex]P = \frac{n!}{k!}[/tex]
➽ The formula for a cyclical permutation is (n – 1)!
**
A combination is a collection of some or all objects regardless of their order.
➽ The formula for the combination is C(n, r) = n!/(r! (n – r)!
**
Factorial, which is sequential multiplication and starts or starts from the number 1 to the number in question, so the factorial of a natural number is the result of multiplying positive integers and less than or also with n.
Example factorial =
[tex]\begin{gathered} \boxed{ \begin{array}{c|c} \underline{\rm Faktorial\:Number} & \underline{ \rm Result}\\ \rm1!&\rm 1 \\ \rm 2! & \rm 2\times1=2\\ \rm 3! & \rm 3\times2\times1=6\\ \rm4! & \rm 4\times3\times2\times1=24\\ \rm 5! & \rm 5\times4\times3\times2\times1=120\\ \rm 6! &\rm 6\times5\times4\times3\times2\times1=720\\ \rm 7! &\rm 7\times6\times5\times4\times3\times2\times1=5.040\\ \rm 8! &\rm 8\times7\times6\times5\times4\times3\times2\times1=40.320\\ \end{array}}\end{gathered}[/tex]
*note: if the result of the factorial number in the box is not visible, swipe to the side
Jawab:
Thyroparathyrodheisazeyia = 3.7401645e+20 word order
Penjelasan dengan langkah-langkah:
"Thyroparathyrodheisazeyia"
t = 2
h = 3
y = 3
r = 3
o = 2
p = 1
a = 4
d = 1
e = 2
i = 2
s = 1
z = 1
Number of letters = 25
Double element =
t = 2h = 3y = 3r = 3o = 2a = 4e = 2[tex]P = \frac{n!}{k!} = \frac{25!}{4! \times 3! \times 3! \times 3! \times 2! \times 2! \times 2!} = \frac{1.551121e+25}{41.472}[/tex]
[tex]\boxed{\tt {{\colorbox{pink}{P = 3.7401645e+20 word order}}}}[/tex]
────────────── ೄྀ࿐ ˊˎ-
#menantang
#lumayan
#susah (╥﹏╥)
Learn More:Permutations of words "Ijin", "Off", "Mulai", "Besok" = brainly.co.id/tugas/44865081word order of "Squid Game" = brainly.co.id/tugas/45040607how many word order of -Selesai -Sudah -Kuis -Nyaa = brainly.co.id/tugas/45089792Answer Details:Subjects: Mathematics
Class: 12 High School
Material: Chapter 7-rules of counting
Categorization Code: 12.2.7
Keywords: Permutations of the word "Thyroparathyrodheisazeyia" and Factorial
16. Berikut ini merupakan kriteria keyword yaitu...trendy dan updatedBrelevan dan updatedsimpel dan mudahD trendy dan simpelE relevan dan balance
Jawaban:
simpel dan mudah
#backtoschool2020
17. Amoeba membelah diri menjadi 2 setiap 10 menit. Jika mula mula terdapat 20 amoeba. Maka banyak amoeba selama 1 jam adalah ... A. 40 amoeba B. 60 amoeba C. 80 amoeba D. 100 amoeba
Penjelasan dengan langkah-langkah:
20 amoebamembelah 2 setiap 10 menit1j = 60m = 6× membelah20, 40, 80, 160, 320, 640
Jadi, banyaknya amoeba setelah 1 jam adalah 640 amoeba (jawabannya salah semua)
#SemogaBisaMembantu
#27November2020
18. >>> Permutations - Laxaoxanox- Phyrilancquain
Answer :
3,628,800
87,178,291,200
Explanationwithsteps
Laxaoxanox = 3,628.800
L : 1
A : 1
X : 1
A : 1
O : 1
X : 1
A : 1
N : 1
O : 1
X : 1
Word Order : 10 x 9 x 8 x 7 x 6 x 5 x 4 x 3 x 2 x 1
Word Order : 3.628.800!
3,628 .800 !
phyrilancquain : 87,178,291,200
P : 1
H : 1
Y : 1
R : 1
I : 1
L : 1
A : 1
N : 1
C : 1
Q : 1
U : 1
A : 1
I : 1
N : 1
word order : 14x13x12x11x10x9x8x7x6x5x4x3x2x1
word order : 87,178,291,200
√GIVE ANSWER√
19. Quiz (580/580)Permutations :- Last- Quiz
Jawaban:
L = 1
a = 1
s = 1
t = 1
....
jumlah huruf : 4
unsur ganda : -
....
[tex] \tt P = 4![/tex]
[tex] \tt P = 4 \times 3 \times 2 \times 1[/tex]
[tex] \tt P = 12 \times 2[/tex]
[tex] \tt P = 24 \: susunan[/tex]
___________________________
Q = 1
u = 1
i = 1
z = 1
....
jumlah huruf : 4
unsur ganda : -
....
[tex] \tt P = 4![/tex]
[tex] \tt P = 4 \times 3 \times 2 \times 1[/tex]
[tex] \tt P = 12 \times 2[/tex]
[tex] \tt P = 24 \: susunan[/tex]
#❁#❁#❁#❁#❁#❁#❁#❁#❁#❁#
kesimpulan
permutasi kata Last = 24 susunan
permutasi kata Quiz = 24 susunan
___________________________
koreksi jika salah
sekian dan terima kasih
Lastjumlah huruf = 4
tidak ada unsur ganda
---------
4!
= 4 × 3 × 2 × 1
= 12 × 2
= 24 susunan
permutasi kata Last adalah 24 susunan
><><><><><><><><><><><><
Quizjumlah huruf = 4
tidak ada unsur ganda
---------
4!
= 4 × 3 × 2 × 1
= 12 × 2
= 24 susunan
permutasi kata Quiz adalah 24 susunan
><><><><><><><><><><><><
20. one of the expression used to recap a presentation
power point. because the usually offer creative and by feelings
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