what is the density of diamond that has a mass of 70g and volume of 20cm³
1. what is the density of diamond that has a mass of 70g and volume of 20cm³
Jawaban:
density = mass/ volume = 70g/20 cm³ = 3,5 g/cm³
2. 1. A cube has length of 7 cm a width of 8 cm and a height of 2 cm. What is its volume? 2. The density if aluminum is 2.7 g/ml. If the aluminum has a volume of 20 ml, what is the mass of the aluminum? 3. A marble has a volume of 20 ml. It also has a mass of 10g. Calculate the density of the marble. Tolong sertakan cara mengerjakannya
1. its volume = 7 × 8 × 2
= 112 cm
2.mass = the density × volume
= 2,7 g / ml × 20 ml
= 54 gram
3.the density= mass / volume
= 10 / 20
= 0,5 g / ml
semoga bermanfaat
3. If 5 litres of a liquid has a mass of 850 g what is the density of the liquid in g/cm³
Jawaban:
0,17 g/cm^3
Penjelasan:
mass = 850 g
volume = 5 litres = 5.000 cm^3
density = mass/volume
= 850/5.000
= 0,17 g/cm^3
4. An alloy is made by combining 900 g of copper with 400 g of iron. If the densityof copper is 9 g/cm and density of iron is 8 g/cm', what is the density of the alloy?(assume that the volume of each metal does not change during mixing.)
ρ(cop) = 9 gr/cm³
ρ(iron) = 8 gr/cm³
ρ = m/Vol
Vol = m/ρ ~ constant!
ρ' = ρ(cop) + ρ(iron)
= 9 + 8
= 17 gr/cm³ ~ 17 × 10³ kg/m³ ✓✓
5. A measuring cylinder has a mass of 120 g when empty. When it contains 50 cm3 of a liquid, the total mass of the measuring cylinder and the liquid is 160 g. What is the density of the liquid?
Mass of cylinder (empty) = 120 gram
Mass of cylinder (with liquid) = 160 gram
Volume of liquid = 50 cm³
Density of the liquid (ρ) = ?
Answer:
Find the mass of liquid
With liquid - Empty
= 160 gram - 120 gram
= 40 gram
So, the mass of the liquid is 40 gram
Find the density of the liquid
[tex]\rho=\frac{mass}{Volume} \\\rho=\frac{40\ gr}{50\ cm^3} \\\rho=\frac{40}{50}\ gr/cm^3 \\\rho=\frac{4}{5}\ gr/cm^3 \\\boxed{\rho = 0,8\ gr/cm^3}\\or\\\boxed{\rho = 800\ gr/cm^3}\\[/tex]
Hope it helps :)
6. PRACTICE EXAMPLE B: A 11.3 mL sample of CH3OH (d = 0.793 g/mL) is dissolved in enough water to produce 75.0 mL of a solution with a density of 0.980 g/mL. What is the solution concentration expressed as (a) mole fraction H20; (b) molarity of CH2OH; (c) molality of CH4OH?
Jawaban:
Take a 1.0 L volume of the solution
This will have mass = 980 g
It will contain 11.3 mL/ 75 mL solution * 1000 mL/L solution = 150.67 mL CH3OH
Mass of CH3OH = 150.67 mL * 0.793 g/mL = 119.5 g
Solution is therefore 119.5 g CH3OH + (980 g - 119.5 g) = 860.5 g wtaer
molar mass CH3OH = 32 g/mol
Mol CH3OH = 119.5 g / 32 g/mol = 3.73 mol in 860.5 g H20
Mol in 1000 g H20 = 1000 g H20 / 860.5 g H20 * 3.73 mol = 4.33 mol in 1.0 kg water
Molality = 4.33 m
Calculate mol fraction :
CH3OH = 4.33 mol
H20 = 1000 g / 18 g/mol = 55.55 mol
Total moles = 59.88 mol
mol fraction CH3OH = 4.33 mol / 59.88 mol = 0.072
Mol fraction H20 = 55.55 mol / 59.88 mol = 0.928
mol fraction has no units. Sum of mol fractions = 1.0
Penjelasan:
SEMOGA MEMBANTU MU
SEMOGA MEMBANTU MUJADIKAN JAWABAN SAYA SEBAGAI TERBAIK DAN TERCERDAS
7. A solution of H2SO4 with a molal concentration of 8.010 m has adensity of 1.354g/mL. What is the molar concentration of thissolution?
Answer with explanation:
You are given a solution of sulphuric acid with a molal concentration of 8.010 m and its density is 1.354 g/mL.
And we also know that the molar mass of sulphuric acid which is 98.079 g/mol.
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With the known datas, we work out the molar concentration in mol/L.
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The relation between molarity, molality and density is described within the following equation.
[tex]\frac{1}{m} = \frac{d}{M}-\frac{Mr}{1000}[/tex]
Where,
Density (d) = 1.354 g/mL
Molecular mass of solute (Mr) = 98.079 g/mol
Molality (m) = 8.010 m
Molarity (M) = ... mol/L
◈ ◈ ◈
So then,
[tex]\frac{1}{8.010\ m} = \frac{1.354\ g/mL}{M}-\frac{98.079\ g/mol}{1000}[/tex]
[tex]0.1248\ m = \frac{1.354\ g/mL}{M}-0.098079\ g/mol[/tex]
[tex]\frac{1.354\ g/mL}{M} = 0.098079\ g/mol+ 0.1248\ m[/tex]
[tex]\frac{1.354\ g/mL}{M} = 0.222879\ g/mmol[/tex]
[tex]M = \frac{1.354\ g/mL}{0.222879\ g/mmol}[/tex]
[tex]M = 6.075\ mol/L[/tex]
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Therefore, the molar concentration of said acid solution is 6.075 mol/L.
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~I hope this helps you~
8. eCalculate the pressure at the bottom of an oil storage tank of depth 2.50 m. The oil has a density of 980 kg/m3 andg= 10 m/s?
Jawaban:
980 kg/m3 . 10 m/s2 . 2.50 m
= 24,500 Pa
= 24,5 kPa
9. A bar of gold has a mass of 3,8 kg. If the density of gold is 19 g/cm3, what is the volume of the gold?
Penjelasan:
so, the bar of gold has a mass : 3,8 kg ⇒ 3800 g
and the density of gold is : 19 g/cm³
this is the formula : Volume = mass / density
V = 3800 g / 19 g/cm³
V = 200 cm³
the answer is : V = 200 cm³
10. the metal uranium has a density of 19g/cm pangkat 3 ...what is the mass of a block of uranium with a volume of 21,5 cm pangkat 3...
massanya adalah = 21,5 x 19 g = 408,5 gramm=ro×v
=19×21,5
=408,5 g
=0,4085 kg
11. The principal solute in vinegar is acetic acid (CH3COOH).If a sample of vinegar has 5.5% w/w acetic acid and a density of 1.006 g/ml, what is the molarity of acetic acid?
Penjelasan:
Zat terlarut utama dalam cuka adalah asam asetat (CH3COOH). Jika sampel cuka memiliki asam asetat 5,5% b / b dan densitas 1,006 g / ml, berapakah molaritas asam asetat?
12. What is the density of a substance that has a volume of 5,5 cm3 and a mass of 10g?
Jawaban:
1,81 g/cm³
Penjelasan:
Density=Mass/Volume
=10/5,5
=1,81 g/cm³
Density=Massa Jenis
Mass=Massa
Volume=Volume
13. A metal cube of side 1 cm has a mass of 100 g. Calculate the density of the metal cube in gm/cm3 and in kg/cm3
Jawab:10g
Penjelasan dengan langkah-langkah:
14. A solid pentagonal pyramid has a mass of 5000 g. It is made of material with a density of 6 g.cm3. given that the base area of the pyramid is 30cm2, find its height
Jawaban:
30cm2 =( 1/2 x 6 )x t
30 cm² = 3 x t
t = 30/3
t = 10
15. An object has a mass of 10 grams and volume of 2mL. What is the density of the object
Jawaban:
ro(density)=m:v
10:2=5
Penjelasan:
16. a metal cube of side 1 cm has a mass of 100g. Calculate the density of the metal cube in:a. g/cm³b. kg/cm³
Jawaban:
kubus logam dengan sisi 1 cm memiliki massa 100g. Hitung massa jenis kubus logam di:
a. g / cm³
b. kg / cm³
diket
r kubus= 1cm
m=100g
cari volume kubus
v kubus = s x s x s
= 1 x 1 x 1
= 1 cm³
ρ=m/v
a.dalam g/cm³
ρ=100/1cm³
=100 g/cm³
b. dalam kg/cm³
ubah satuan masa dari g ke kg
100g =0,1kg
ρ=m/v
=0,1kg/1cm³
=0,1 kg/cm³
17. steel block has mass 40 g it is in the form of a cube each edge of the cube is 3 cm long so what is the density
Jawaban:
1.481g/cm³
Penjelasan:
density = mass/ volume,
volume of cube is s³
mass = 40 g
v = 3.3.3= 27 cm
density = 40/27
= 1.481 g/cm³
18. Calculate the density of mercury if 500cm³ has a mass of a 6.60kg. give your answer om g/cm³
Mercury density = mass : volume
6.60 kg = 6.600 g
= 6.600 : 500
= 13,2 g/cm^3
Sorry if i wrong
19. A cube of copper has a mass of 600kg. copper has a density of 9.3g/cm³. Calculate the length of each side of the cube to the nearest mm.
This is how you solve it
volume = 600.000 / 9,3 (we make 600 kg to 600.000 g because the density use gram to)
Volume = 64.516 cm³ (approximately)
Lenght = 254 cm
Lenght = 254,0 mm
20. The density of carbon tethacholride is 1.59 g/ml. Calculate the volume of 26.4 grams of the liquid.tolong dijawab besok dikumpulkan
V= m/d
= 26,4/1,59
= 16,604 ml3 ( ml pangkat 3 )
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