Find the area of the shaded part in the figure below
1. Find the area of the shaded part in the figure below
4. Area = 49.2075 m²
5. Area = 63.25 m²
Penjelasan/Explanation
Number 4
The area of that figure equals to the area of the square minus the area of the semicircle.
The length of each side: s = 9 mRadius of semicircle: r = ½sA = s² – ½πr²
⇔ A = s² – ½π(½s)²
⇔ A = s² – ½(¼πs²)
⇔ A = s² – (1/8)πs²
⇔ A = s²[1 – (1/8)π]
⇔ A = 9²[1 – (1/8)×3.14]
⇔ A = 81(1 – 0.3925)
⇔ A = 81(0.6075)
⇔ A = 49.2075 m²
Number 5
The area of that figure equals to the sum of the area of the right-angled triangle and the area of the semicircle.
Base of triangle: b = 8 mHeight of triangle: h = 6 mRadius of semicircle: r = (½×10) m = 5 mA = ½bh + ½πr²
⇔ A = ½(bh + πr²)
⇔ A = ½(8×6 + 3.14×5²)
⇔ A = ½(48 + 3.14×25)
⇔ A = ½(48 + 78.5)
⇔ A = ½(126.5)
⇔ A = 63.25 m²
KESIMPULAN/CONLUSION4. Area = 49.2075 m²
5. Area = 63.25 m²
2. find the area of the shaded partarea of figure
[tex] \frac{1}{4} \times \frac{22}{7} \times 14 \times 14 + 2 \times \frac{1}{2} \times \frac{22}{7} \times 7 \times 7 \\ \\ 154 + 154 \\ \\ 308 \: {cm}^{2} [/tex]
3. Find the area of the shaded part of the figure.
Jawaban:
81
Penjelasan dengan langkah-langkah:
15*15=225
12*12=144
225-144=81
4. The figure shows two circles of radii 14 cm and 35 cm. Find the area of the shaded part of the figure. ( take 22/7)
Jawab:
Penjelasan dengan langkah-langkah:
r1 = 14 cm
r2 = 35 cm
radius shade area = 35+14 = 49
shade are = 1/2πr²
= 1/2 x 22/7 x 49²
= 3773
may it helps you with the question hihi :D
5. in the figure below BD=DE find the area of the shaded part
Answer:
1,728 cm²
Explanation with steps:
BD = DE = 1/2 x 96 cm = 48 cm
area of the shaded part = area of ABC - area of ADC
area of ABC
= 0.5 x AC x BE
= 0.5 x 72 cm x 96 cm
= 3,456 cm²
area of ADC
= 0.5 x AC x DE
= 0.5 x 72 cm x 48 cm
= 1,728 cm²
so the area of the shaded part is
= 3,456 cm² - 1,728 cm²
= 1,728 cm²
6. The area of shaded part is . . . . cm2
Jawaban:
400
Penjelasan dengan langkah-langkah:
20 × 20 = 400 cm²
semoga membantu
jadikan saya tercerdas dong
7. Find the area of the shaded part.
We have width 8 cm. Each of the width that has been bisect is 4 cm. Now, we need to find the smallest white triangle (with the base 4 cm) and a triangle with the base 8 cm.
[tex] \displaystyle \underset{\text{White}}{\text{Area}} = \frac{1}{2} \times 4 \times 14 = 28 [/tex]
[tex] \displaystyle \underset{\text{White}}{\text{Area}} = \frac{1}{2} \times 8 \times 14 = 56 [/tex]
Now, to find the shaded area part, we just have to subtract all of them.
[tex] \displaystyle \underset{\text{shaded part}}{\text{Area}} = 56 - 28 = 28 [/tex]
8. Find the area of the shaded part in the figure belom! Jangan asal ya :)
Penjelasan dengan langkah-langkah:
L 1/4 lingkaran (r = 14 cm)
= 1/4 x 22/7 x (14 cm)²
= 154 cm²
9. find the area of shaded part of each figure. A.Area of big semicircleB.Area Of small semicircleC.Area of Shaded part
Jawaban:
Jawaban: A
Penjelasan dengan langkah-langkah:
Jika dilihat bagian yg lebih besar memiliki warna gelap dan yg kecil bewarna cerah. Itu caranya
10. Find the area of the shaded part
Jawaban:
32cm²
Penjelasan dengan langkah-langkah:
Find The Area Of the Clear part :
8 x 4 : 2 =16
8 x 4 : 2 =16
16 + 16 = 32
Find The Total Area on the square :
8 x 8 = 64
Find The Area Of the Shaded part :
64 - 32 = 32cm²
11. in the figure below BD=DE find the area of the shaded part
AREA
═══════════════════════════
Solutions that match the question!
Solution :The area of the large triangle minus the area of the small triangle.
BD = DE = 1/2 BE = 1/2 96 = 48 cm
Area 1
= 1/2 × 72 × 96
= 72 × 48
= 3.456 cm²
Area 2
= 1/2 × 72 × 48
= 72 × 24
= 1.728 cm²
[tex]\\[/tex]
Area of the shaded part :
= Area 1 - Area 2
= 3.456 - 1.728
= 1.728 cm²[tex]{ \green{ \boxed{ \boxed{ \sf{ {Answer \: by : AdhidMagelang}}}}}}[/tex]
12. find the area of the shaded parttolong dengan cara
Cara:
Dicari dulu luas kedua segitiga.
[tex]l = \frac{axt}{2} [/tex]
L = Luas a = alas t = tinggi
[tex]l 1 = \frac{12x12}{2} = 72cm {}^{2} [/tex]
[tex]l2 = \frac{12 \times 5}{2} = 30cm {}^{2} [/tex]
angka 5 dari mana? dari 12 - 7 = 5 cm, yang merupakan tinggi segitiga kecil.
[tex]ls = 72 - 30 = 42cm {}^{2} [/tex]
13. Find the total amount of rectangles that contain the shaded part in the figure below.
Jawaban:
1
Penjelasan:
maaf kalau salah
14. find the area of the shaded part of the rug
(3,14 × 50cm ×50cm) - (2×¼×3,14×50cm×50cm)
= 7.850cm² - 3.925cm²
= 3.925cm²
i'm sorry if i made a mistake
15. calculate the area of the shaded part of the shape
Jawab:
5,375 [tex]cm^2[/tex]
Penjelasan dengan langkah-langkah:
The area of square is
5×5 = 25
The area of circle is
[tex]\pi[/tex]x2,5x2,5
3,14x2,5x2,5
19,625
The area of shaded part is 25-19,625 = 5,375 [tex]cm^2[/tex]
16. Calculate the shaded area of the figure
Ibaratkan :
segitiga besar = a
segitiga kecil = b
Diketahui :
panjang alas a = 62 cm
panjang alas b = 62 cm
tinggi a = 30 cm
tinggi b = 21 cm
Jawab :
Luas arsiran = (luas a)-(luas b)
L = (62 x 30/2) - (62 x 21/2)
L = (1860/2) - (1302/2)
L = 930 - 651
L = 279 cm^2
Maaf jika ad kesalahan :)
17. the figure below is made up of a rectangle and a square. the ratio of the area of the square to area of the rectangle is 2:5. if 0.25 of the square is shaded, what fraction of the figure is unshaded?
gambar dibawah ini dibuat dari sebuah persegi panjang dan sebuah persegi. perbandingan daerah persegi dibandingkan dengan persegi panjang adalah 2:5 jika 0,25 dari persegi tersebut diarsir. berapa bagian dari gambar yang tidak diarsir?
18. Find the area of the shaded part!
[tex]luas \: segitiga = \frac{alas \times tinggi}{2}[/tex]
[tex]luas \: persegi = panjang \: \times \: lebar[/tex]
Jumlah bangun,
2 Segitiga (Alas dan Tinggi = 6 cm)
1 Persegi Panjang (Panjang = 20 cm dan Lebar = 6 cm)
Maka,
[tex]2 \times luas \: segitiga + luas \: persegi[/tex]
[tex] = 2 \times \frac{6 \times 6}{2} + 20 \times 6[/tex]
[tex] = 36 + 120[/tex]
[tex]luas = 156 \: {cm}^{2} [/tex]
Tolong jadikan jawaban terbaik ya! :)
19. find the total area of the shaded region in the figure
Jawaban:
The total area of the shaded reagion in the figure = 76 cm
Penjelasan dengan langkah-langkah:
Total area of the shaded region:
[tex] = \frac{(5 + 7 + 6) \times 8}{2} + \frac{(7 + 6) \times 8}{2} - 2 \times \frac{8 \times 6}{2}[/tex]
[tex] = 72 + 52 - 48 = 76 \: {cm}^{2} [/tex]
20. The figure is made up of 4 identical small circles of radius 3cm and a bigger circle of radius 14 cm. Find the area of the shaded part of the figure (take π = 3,14)
Jawaban:
Correct option is B)
Let r,ρ,R be the radii of small, medium and big circles respectively.
Radius of small circle =r=4 cm.
Radius of medium circle =ρ=4×
2
3
=6 cm. (small:medium=2:3)
Radius of big circle =R=2×6=12 cm.
(a) Area of unshaded part =2×πr
2
+2×πρ
2
=2π(4
2
+6
2
)=104π cm
2
Area of big circle =πR
2
=12
2
π=144π
Area of shaded part =πR
2
−104π=144π−104π=40π cm
2
(b) Fraction of area shaded =
144π
40π
=
18
5
.
∴ The answer is [B].
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