Triangle ABC is a right-angled triangle. Find
1. Triangle ABC is a right-angled triangle. Find
Triangle ABC is a right-angled triangle. Find
∠ABC = 90°
∠DBC = 25°
∠BAD = 60°
∠ABD = 70°
∠ADB = 55°
∠DCB = 32°
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2. A triangle with 3 equal sides is a/ana. right angled triangleb. isosceles trianglec. equilateral triangled. scalene triangle
Jawaban:
the answer is= C. equilateral triangle
Jawaban:
Segitiga dengan 3 sisi sama panjang adalah a/an
Sebuah. segitiga siku-siku
b. segitiga sama kaki
c. segitiga sama sisi
d. segitiga siku-siku
Penjelasan dengan langkah-langkah:
C.equilateral triangle
3. 1.) Triangle MNO is a right-angled triangle and triangle NOP is an isosceles triangle. MO is perpendicular to OP. ∠OMN = 53°. Find ∠OPN.
Penjelasan dengan langkah-langkah:
< MON = 90-53= 37°
< NOP = 90-37= 53° = < PNO
=> <OPN=180-(53+53)
=180-106=74°
goodluck
4. 1. find perimeter and area of right Triangle of ABC whit leght AB= 12cm BC= 5cm CA= 13cm2. right triangle which elbow is C whit leght AB= 15 AC=12 the area of triangle ABC is ....... cm²
No.1
Perimeter = 12 + 5 + 13 = 30 cm
Area = ½ × 12 × 5 = 30 cm²
No.2
Area = ½ × AC × BC
Area = ½ × 12 × √(15²-12²)
Area = 6 × √(225 - 144)
Area = 6 × √81
Area = 6 × 9
Area = 54 cm²
5. a wooden board is shaped right angled triangle of which the length of the right angle is 13 cm and40 cm. the area of the wooden board is
Jawab:
13*40:2
13*20
=260 m²
semoga membantu
Jawab:
260 cm²
Penjelasan dengan langkah-langkah:
sisi saling tegak lurus siku2 berarti alas dan tinggi
maka L = 1/2*a*t
=1/2 *13 cm * 40 cm
= 1/2 * 520 cm²
=260 cm²
maaf kalau salah
no copas
6. a wooden board is shaped right angled triangle of which the length of the right angle is 13 cm and40 cm. the area of the wooden board is
Jawab:
260 cm²
Penjelasan dengan langkah-langkah:
sisi saling tegak lurus siku2 berarti alas dan tinggi
maka L = 1/2*a*t
=1/2 *13 cm * 40 cm
= 1/2 * 520 cm²
=260 cm²
maaf kalau salah
no copas
7. In the figure, ABCD is a parallelogram, CDF is a right-angled triangle, and CGF and DEF are straight lines. If the area of ACDF is 60 cm and 2CG = GF, find the area of the parallelogram ABCD.
Penjelasan dengan langkah-langkah:
2CG = CF
Area of ABCD = CD • CG
Area of CDF = (CD • CF)/2 = 60 cm²
Area of CDF = (CD • 2CG)/2 = 60 cm²
Area of CDF = CD • CG = 60 cm² = Area of ABCD.
So, the area of ABCD is 60 cm²
8. (4) EFG is a right-angled triangle. EFH is a straight line. FHJ is an isosceles triangle. Find LGFJ. J 52° G H 78° F E
segitiga
∆FHJ sama kaki
∠JFH = ∠JHF = (180° - ∠FJH)/2
∠JFH = (180° - 52°)/2 = 64°
∠GEF + ∠GFE = 90°
78° + ∠GFE = 90°
∠GFE = 90° - 78° = 12°
∠GFJ
= 180° - ∠GFE - ∠JFH
= 180° - 12° - 64°
= 104°
9. Length of right triangle is (x+2)cm (3x)cm and (4x-6) cm If the circumference is 60 cm. The area of the triangle is ....... cm2
[tex](x+2)+(3x)+(4x-6)=(8x-4)=60[/tex]
so, [tex]x=8[/tex]
length of the triangle is 10 cm, 24 cm, and 26, cm
In this triple pytagoras, the area is
[tex]\frac{1}{2} .10.24=120cm^{2}[/tex]
10. Length of right triangle is (x+2)cm (3x)cm and (4x-6) cm If the circumference is 60 cm. The area of the triangle is ....... cm2
x + 2 + 3x + 4x - 6 = 60
8x - 4 = 60
8x = 64
x = 8
8 + 2 = 10cm
3(8) = 24cm
4(8) - 6 = 26cm
(kali 2 dari segitiga siku-siku 5, 12, 13)
Ini merupakan segitiga siku-siku jadi 10 dan 24 merupakan alas dan tinggi jadi tinggal masukkan ke rumus luas segitiga
10 * 24 * 1/2 = 120 cm^2
ʕっ•ᴥ•ʔっ
[tex] 120 [/tex]
DEFINITION
Circumference is sum of the length of every outer sides.
ANSWER
Let [tex]a[/tex], [tex]b[/tex], and [tex]c[/tex] be the length of right triangle consecutively. Suppose [tex] C [/tex] is the circumference, then by definition
[tex] C = a + b + c \\ \Leftrightarrow C = (x+2)\text{ cm} + 3x \text{ cm} + (4x-6) \text{ cm} \\ \Leftrightarrow C = (8x - 4) \text{ cm} \\ \Leftrightarrow 60 \text{ cm} = (8x - 4) \text{ cm} \\ \Leftrightarrow 60 = 8x - 4 \\ \Leftrightarrow 64 = 8x \\ \therefore \: x = 8 [/tex]
By substituting [tex] x [/tex] with [tex] 8 [/tex], one can obtain
[tex] a = (8+2) \text{ cm} = 10 \text{ cm} \\ b = (3\times 8) \text{ cm} = 24 \text{ cm} \\ c = (4\times 8-6) \text{ cm} = 26 \text{ cm} [/tex]
Since side [tex] c [/tex] is the longest side ([tex] 26 \text{ cm} [/tex]), side [tex] c [/tex] is the hypothenuse.
Then, the area can be calculated as shown below
(Let [tex] A [/tex] be the questioned area)
[tex] A = \frac{1}{2} ab \\ \Leftrightarrow A = \frac{1}{2} \times 10\text{ cm} \times 24\text{ cm} \\ \therefore \: A = 120\text{ cm}^2 [/tex]
CONCLUSION
Therefore, the area of the right triangle is [tex] 120 \text{ cm}^2 [/tex].
11. What is the area of the right triangle shown below
ANSWER:
60.
Penjelasanya :
(theorema phytagoras) a=[tex]\sqrt{b^{2} -c^{2} }[/tex]
a= 17[tex]\sqrt{17^{2}-8^{2} } = \sqrt{289-64}[/tex]
a=[tex]\sqrt{225} =[/tex]15
(the area of the right triangle) :
1/2 x a x h
1/2 x 8 x 15
= 60
ur welcome:)
12. what is the ice cream shape? is ice cream shape is.... a. coneb. cubec. arrowd. right triangle
Jawaban:
A. Cone
Penjelasan:
A. Cone = kerucut
B. Cube = kubus
C. Arrow = panah
D. Right triangle = segitiga siku-siku
Jadi jawabannya A karna bentuk es krim tidak seperti jawaban lainnya.
Semoga membantu^^
13. apa arti dari right triangle?
Jawabannya segitiga siku sikuArti dari right triangle adalah segitiga siku-siku
14. right triangle adalah ikon untuk membuat
Jawaban:
kotak
Penjelasan:
15. if one angle of a triangle is equal to the sum of other two angles then the triangle is-:i) an isoscales triangle.ii) an obtuse triangle.iii) an equilateral triangle.iv) a right triangle.
Jawaban:
iii) an equilateral triangle
mungkin
maafkalausalahya.
16. the measures of three sides of a triangle are 9,16,20. determine whether the triangle is a right triangle. explain your answer..
i dont know what you say
17. right triangle adalah ikon untuk membuat
Jawaban:
kotak
Penjelasan:
18. ABCD is a parallelogram. AED is a right-angled triangle. Find m
Jawaban:
gak bisa bahasa Inggris
19. P(1,6),Q(-2,1) and R(3,-2) show that triangle PQR is a right-angled isosceles triangle qnd calculate the area of triangle
Jawaban:
p+q=2÷3=4,222 sedangkan di titik tengah r 3×2+4÷3=5 t=234×342÷345=3.543=(876×546)=453r=3×2=6
Penjelasan dengan langkah-langkah:
segitiga r=234
t=244-342=432
x=jari-p146
x=110-1=109
20. if triangle ABC and triangle DEF are similiar,the value of x + y=.... cm panjang a ke C = 18cm
DE = 5 cm (triple pythagoras)
[tex] \frac{bc}{ef} = \frac{ac}{df} \\ \frac{x}{3} = \frac{18}{4} \\ 4x = 54 \\ x = \frac{54}{4} \\ x = 13.5[/tex]
[tex] \frac{ab}{de} = \frac{ac}{df} \\ \frac{y}{5} = \frac{18}{4} \\ 4y = 90 \\ y = 22.5 [/tex]
jadi x + y = 13,5 + 22,5 = 36,0
semoga membantu
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