1. Given K(2, 0), L(4, -4), M(6, 0). Determine the value of N, so that if the four points are connected it will form a rhombus.2. A function is expressed by the formula f(x) = ax + b. If f(2) = -3 and f(-3) = 7, determine the values of a and b.______________Feliz respuesta!
1. 1. Given K(2, 0), L(4, -4), M(6, 0). Determine the value of N, so that if the four points are connected it will form a rhombus.2. A function is expressed by the formula f(x) = ax + b. If f(2) = -3 and f(-3) = 7, determine the values of a and b.______________Feliz respuesta!
Jawaban:
1.) N = (4,4)
2.) a = -2
b = 1
Penjelasan dengan langkah-langkah:
2.) f(x) = ax + b
f(2) = 2a + b = -3
f(x) = ax + b
f(-3) = -3a + b = 7
f(2) = 2a + b = -3
f(-3) = -3a + b = 7
-------------------------- -
2a - (-3a) = -3 - 7
2a + 3a = -10
5a = -10
a = -10/5
a =-2
2a + b = -3
2(-2) + b = -3
-4 + b = -3
b = -3 - (-4)
b = -3 + 4
b =1
a = -2
b = 1
________________________________
2. Given that the coordinate of point A (8, −1) and B (2, − 13). The gradient of a line passes through points A and B is… *A.− 3B.−1/3C.1/2D.2
[tex]{\purple{\boxed{\boxed{\pink{Answer + Explain}}}}}[/tex]
m = ∆y/∆x
=> y2 –y1/x2 –x1
m = –13 –(–1)/2 –8
m = –13 + 1/–6
m = –12/–6
m = 2
So, the gradient of a line through points A and B is 2 [tex]{\purple{\boxed{\boxed{\blue{D}}}}}[/tex]
3. 1) (4, 5) and (-3, -1)2) (-7, 5) and (-1, -6)3) (2, -3) and (2, 4)4) (-3, 2) and (-4, 4)5) (6, -3) and (-4, 2)A. Calculate the gradient between each pair of pointsB Work out the distance between each pair of pointsC. Find the coordinates of the midpoint between each pair of pointsD. Work out the equation of the line (in y = mx + c form) that passes through each pair of points
Jawaban:
kita mwnjawab dengan baik
4. anshi Find the distance between the points (0, 0) and (36, 15)
Jawaban:
Antonie Philips van Leeuwenhoek FRS was a Dutch businessman and scientist in the Golden Age of Dutch science and technology. A largely self-taught man in science, he is commonly known as "the Father of Microbiology", and one of the first microscopists and microbiologists
5. 6. Look at the following points!(1) Date(2) Time(3) Hobby(4) NameAbove are related with the number ...a. (1) and (2)b. (2) and (3)C. (3) and (4)d. only (4)
Jawaban:
A.(1) & (2)
maaf kalau salah
Jawaban:
jawabannya
A. 1 and 2
Penjelasan:
karena pertanyaannya menanyakan angka
6. anshi Find the distance between the points (0, 0) and (36, 15)
Jawaban:
Penjelasan:
Distance² = (36 - 0)² + (15 - 0)²
Distance² = 36² + 15²
Distance² = 1296 + 225
Distance² = 1521
Distance = V1521
Distance = 39
Conclusion :
The distance between the points (0, 0) and (36, 15) is 39.
7. anshi Find the distance between the points (0, 0) and (36, 15)
Jawaban:
अंश (0, 0) और (36, 15) के बीच की दूरी का पता लगाएं
8. anshi Find the distance between the points (0, 0) and (36, 15)
Penjelasan:
anshi Find the distance between the points (0, 0) and (36, 15)
9. anshi Find the distance between the points (0, 0) and (36, 15)
Jawaban:
I wanted to say something ....
I'm afraid of losing you ❤️
10. arti dari "The points (a,0) , ( -2,b) , (c,1.5) lie on the graph in (i). Find the value of a,b and c
Artinya =
Titik (a,0) , (-2,b) , (c,1.5) terdapat pada grafik (i). Temukanlah / tentukanlah nilai a,b dan c
11. if the plot points are A ( -5 , 8) B ( -3 , 2 ) C ( 0 , 3 ) D ( -2 , 9 ) then we reflect the polygon to the y-axis the translate the reflected polygon 7 units right and 4 units down then what would the new plot points be? (with the way)
Jawaban:
mihon maaf saya gak ngerti bahasa inggris ya
12. anshi Find the distance between the points (0, 0) and (36, 15).
Jawaban:
EK BAT KAHU KYA IZAZAT HAI?
TERE ISHQ KI MUJKO ADDAT HAI...❤️
13. anshi Find the distance between the points (0, 0) and (36, 15).
Jawaban:
I'm dancing in the dark
with you between my arms❤️
14. anshi Find the distance between the points (0, 0) and (36, 15).
Jawaban:
yo también te amo❣️
y te amare hasta mi ultimo aliento
15. anshi Find the distance between the points (0, 0) and (36, 15).
Jawaban:
muje na sab pasand hai aghar uska Dil saff ho❤️
16. Given two points P ( 4,5 ) and Q ( -2, -3 ). The distance between P and Q is?... Tolong bantuanya ya guys :)
PQ =
[tex] \sqrt{ {(x2 \: - x1)}^{2} + {(y2 - y1)}^{2} } [/tex]
[tex] \sqrt{ {(4 - ( - 2))}^{2} + {(5 - ( - 3))}^{2} } [/tex]
[tex] \sqrt{ {(4 + 2)}^{2} + {(5 + 3)}^{2} } [/tex]
[tex] \sqrt{ {6}^{2} + {8}^{2} } = \sqrt{36 + 64} [/tex]
[tex] \sqrt{100} = 10[/tex]
The distance between P and Q is 10
17. anshi Find the distance between the points (0, 0) and (36, 15).
Jawaban:
Hands on your body, I don't wanna waste no time
Feels like forever even if forever's tonight
Just lay with me, waste this night away with me
You're mine, I can't look away, I just gotta say
ily ❤️
18. The coordinates of three points are A(1, 1), B(-1, 4) and C(h, k). Given that the gradients of AB, AC and BC are -3a, 3a and a respectively, find the values of h, k and a.
h = 5, k = 7, a = ½
Explanation/Penjelasan
The coordinates of three points are A(1, 1), B(–1, 4) and C(h, k).
Given that the gradients of AB, AC and BC are –3a, 3a and a respectively, we can get
[tex]\begin{aligned}&&m_{\rm AB}&=\frac{y_{\rm B}-y_{\rm A}}{x_{\rm B}-x_{\rm A}}\\\\&\Leftrightarrow&-3a&=\frac{4-1}{-1-1}\\&&&=\frac{3}{-2}\ =\ -3\cdot\frac{1}{2}\\\\&\therefore&a&=\bf\frac{1}{2}\\\\&\therefore&m_{\rm AC}&=3a={\frac{3}{2}}=\frac{y_{\rm C}-y_{\rm A}}{x_{\rm C}-x_{\rm A}}\\&\Leftrightarrow&\frac{3}{2}&=\frac{k-1}{h-1}\\&\Leftrightarrow&\!\!3h-3&=2k-2\quad...(i)\end{aligned}[/tex]
[tex]\begin{aligned}&&m_{\rm BC}&=a={\frac{1}{2}}=\frac{y_{\rm C}-y_{\rm B}}{x_{\rm C}-x_{\rm B}}\\&\Leftrightarrow&\frac{1}{2}&=\frac{k-4}{h-(-1)}\ =\ \frac{k-4}{h+1}\\&\Leftrightarrow&h+1&=2k-8\\&\Leftrightarrow&h&=2k-9\quad...(ii)\end{aligned}[/tex]
[tex]\begin{aligned}&&(ii)\to(i):\\&&\!\!\!\!3(2k-9)-3&=2k-2\\&\Leftrightarrow&6k-27-3&=2k-2\\&\Leftrightarrow&6k-30&=2k-2\\&\Leftrightarrow&6k-2k&=-2+30\\&\Leftrightarrow&4k&=28\\&&\therefore\ k&=\bf7\\\\&&(ii)\implies h&=2(7)-9\\&&&=14-9\\&&\therefore\ h&=\bf5\end{aligned}[/tex]
CONCLUSION/KESIMPULAN
∴ h = 5, k = 7, a = ½
gradient formula :
m = y2 - y1 / x2 - x1
19. A straight line passes through the points A(- 4, 2) and B(2, - 9) Find : (a) the gradient of the line (b) the equation of the line
Jawab:
Penjelasan dengan langkah-langkah:
a.
A(- 4, 2)---> x₁ =-4 and y₁ =2
B(2, - 9) ---> x₂ =2 and y₂ = -9
gradient = (y₂-y₁)/(x₂-x₁) = (-9-2)/(2-4) = -11/-2 = 11/2
b.
y -y₁ =m (x-x₁)
y -2 = 11/2 (x+4)
2y - 4= 11 (x+4)
2y - 4 = 11x + 44
11x - 2y + 48 = 0
20. 27. Look at the following points.(1) Ghanaian.(2) Large.(3) Narrow(4) Wrinkled.Above are the adjectives that show the size showin number ....a. (1) and (2) c. (1) and (4)b. (1) and (3) d. (2) and (3)28. Look at the following points.(1) Good.(2) Small.(3) High(4) Expensive.2.Look at the following points.(1) Good(2) Smail.(3) high(4) Expensive.Above are adjectives which are added -er whenthey are changed into comparative show innumbera. (1) and (2) C. (1) and (4)b. (1) and (3) d (2) and (3)
Jawaban:
27. D. (2) and (3)
28. D. (2) and (3)
Semoga membantu
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